Problem Solving (PS) | Re: What is the equivalent expression of

\((\frac{1}{x+y+z})(\frac{1}{x}+\frac{1}{y}+\frac{1}{z})(\frac{1}{xy+yz+zx})(\frac{1}{xy}+\frac{1}{yz}+\frac{1}{zx})\)=
\((\frac{1}{x+y+z})(\frac{xy+yz+xz}{xyz})(\frac{1}{xy+yz+zx})(\frac{x+y+z}{xyz})\) =\((\frac{1}{xyz})^2\)
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