AkashAvhad wrote:
Niha01 wrote:
HongHu wrote:
Good job thearch. You can also do it this way: 2^5-5(four wins)-1(fivewins)=26.
Can you please elaborate on thisapproach
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Hi Niha01,
Five hands in general, could have any of the following outcomes:
Case 1) All 5 wins
Case 2) 4 wins and 1 loss
Case 3) 3 wins and 2 losses
Case 4) 2 wins and 3 losses
Case 5) 1 win and 4 losses
Case 6) All 5 losses
In the given question, we know there are 3 wins and 9 losses. Hence, the first five hands cannot have
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