Since p is primes and is > 2, then p must be an odd number since 2 is the only even prime number.
I solved by simply plugging in:
p = 5 (a prime) ---> n = 20
Factors of 20 include:
20 1
10 2
5 4
In this factor tree there is a total of 4 even factors means C is the correct answer.
If you aren't convinced after this you should have time to plug in another prime number for p. I finished within 50 seconds using just p =5.
I solved by simply plugging in:
p = 5 (a prime) ---> n = 20
Factors of 20 include:
20 1
10 2
5 4
In this factor tree there is a total of 4 even factors means C is the correct answer.
If you aren't convinced after this you should have time to plug in another prime number for p. I finished within 50 seconds using just p =5.
