Jasonammex wrote:
If (y+3)(y-1)-(y-2)(y-1)=r(y-1), what is the value of y?
(1) r^2=25
(2) r=5
Given information=
(y+3)(y-1)-(y-2)(y-1)=r(y-1)
Question- value of y?
Inference from given information-
(y+3)(y-1)-(y-2)(y-1)=r(y-1)
(y+3)- (y-2)= r (y-1) is common at both the sides of the equation.
y+3-y+2=r
r=5
(y is cancelling out at both sides of equation, so most likely we need one of the statement to produce value of y )
(1) r^2=25
It does not give us a solution for y
(2) r=5
It does not give us a solution
...
