broilerc wrote:
If b and c are constants for which the quadratic equation \(x^2+bx+c=0\) has two different roots, what is the product of the two roots?
(1) One of the roots is 3.
(2) c=6
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Can someone elaborate please?
Viete's theorem states that for the roots\(x_1\) and\(x_2\) of a quadratic equation\(ax^2+bx+c=0\) :
\(x_1+x_2=\frac{-b}{a}\) AND\(x_1*x_2=\frac{c}{a}\) .
Thus for x^2+bx+c=0 the product of the roots will be c/1 = c.
Answer: B.
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