All choices have a factor of 100, so we only concern with the factor other than 100:
A. 6=2*3
B. 7
C. 9=3*3
D. 21=3*7
E. 49=7*7
Check whether combination of 96, 196, 300 has sufficient 3*3 and 7*7 (and a single 2 beside 100):
96= 2^5*3, 196= 2*2*7*7, and 300= 3*100.
Obviously, choice (C) is the answer since it has more factor of 3 than it should have been.
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A. 6=2*3
B. 7
C. 9=3*3
D. 21=3*7
E. 49=7*7
Check whether combination of 96, 196, 300 has sufficient 3*3 and 7*7 (and a single 2 beside 100):
96= 2^5*3, 196= 2*2*7*7, and 300= 3*100.
Obviously, choice (C) is the answer since it has more factor of 3 than it should have been.
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