ravitejapandiri wrote:
If the operation # is one of the four arithmetic operations addition, subtraction, multiplication and division, is (6#2)#4 = 6#(2#4)
(1) 3#2 > 3
(2) 3#1 = 3
We basically need to answer either a YES or a NO for the equation (6#2)#4 = 6#(2#4)
And if we see the equation, then we know for sure that we can answer the question if # is :-
+ or * =>YES, Equation will hold => Sufficient
- or / => NO Equation will not hold => Sufficient
Now, looking
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