rajatchopra1994 wrote:
Raxit85 wrote:
What is the sum of all possible 7-digit numbers that can be constructed using the digits 1, 2, 3, 4, 5, 6 and 7, if each digit can be used only once in each number?
A) 7! * 8888888
B) 3.5! * 8888888
C) 3.5!/2 * 88888888
D) 7!/2 * 8888888
E) 7 *8888888
A) 7! * 8888888
B) 3.5! * 8888888
C) 3.5!/2 * 88888888
D) 7!/2 * 8888888
E) 7 *8888888
Generally the sum of all the numbers which can be formed by using the n distinct digits, is given by the formula:
(n-1)!*(sum of the digits)*(111…..n times)
DearRajatchopra1994,
[color=#ed1c24] Kindly do not copy paste exactly, at least, from other members
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