Bunuel wrote:
How many different positive integers can be formed using each digit in the set {0, 1, 3, 3, 3, 7, 8} exactly once?
A. 160
B. 720
C. 1440
D. 4320
E.5040
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There are 7 digits out of which there are three 3s.
Different ways these can be arranged is 7!/3!, as three 3s can be arranged in 3! Ways we divided total by 3!
7!/3!=7*6*5*4=840.
However 840 is not in choices, and we have to use each digit once. But the numbers starting with 0 actually do
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