If p and q are integers, what is the remainder when p^2 + q^2 is divided by 5?
I. When p - q is divided by 5, the remainder is 1.
If\(p=5, q=4.....p^2+q^2=25+16=41\) ...remainder=1
If\(p=2, q=1.....p^2+q^2=4+1=5\) ...remainder=0
Insuff
II. When p + q is divided by 5, the remainder is 2.
If\(p=3, q=4.....p^2+q^2=9+16=25\) ...remainder=0
If\(p=2, q=0.....p^2+q^2=4+0=4\) ...remainder=4
Insuff
Combined..
From I, when\((p-q)^2\) or\(p^2+q^2-2pq\) is divided by 5, the remainder is 1^2=1.
From II, when\( (p+q)^2\)
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I. When p - q is divided by 5, the remainder is 1.
If\(p=5, q=4.....p^2+q^2=25+16=41\) ...remainder=1
If\(p=2, q=1.....p^2+q^2=4+1=5\) ...remainder=0
Insuff
II. When p + q is divided by 5, the remainder is 2.
If\(p=3, q=4.....p^2+q^2=9+16=25\) ...remainder=0
If\(p=2, q=0.....p^2+q^2=4+0=4\) ...remainder=4
Insuff
Combined..
From I, when\((p-q)^2\) or\(p^2+q^2-2pq\) is divided by 5, the remainder is 1^2=1.
From II, when\( (p+q)^2\)
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