cantaffordname wrote:
Archit3110 wrote:
Bunuel wrote:
What is the average (arithmetic mean) of 8a and 4b?
(1) a + b = 5
(2) 2a + b = 11
(1) a + b = 5
(2) 2a + b = 11
average (arithmetic mean) of 8a and 4b
re written as
4a+2b ; 2*(2a+b)
#1
a+b=5
a & b not known insufficeint
#2
2a+b=11
so 2*11; 22
IMO B ;sufficient
Can't we put the value as "A= 5-B" and solve the equation for the first option?
Posted from my mobile device /quote]
I went down the same rabbit hole. Someone please correct me if I am wrong!
We cannot do this, because
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