Bunuel wrote:
FRESH GMAT CLUB TESTS QUESTION
The length of rectangle B is x percent less than the length of rectangle A, and the width of rectangle B is y percent, greater than the width of rectangle A (where both x and y are greater than 0 and less than 100). Is the area of rectangle A greater than the area of rectangle B?
(1) x = y
(2) x + y = 20
Rectangle A: L=a, W=b; Rectangle B: L=c=a(1-x/100), W=d=b(1+y/100)
\( Question:ab>a(1-x/100)b(1+y/100)?…ab>(ab/100^2)(100-x)(100+y)…\)
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