rohan2345 wrote:
There are 8 marbles in a jar, 5 are red and 3 are green. If 4 marbles are selected at random form the jar, what is the probability that at least one red marble and one green marble will be selected?
(A) 4/5
(B) 10/11
(C) 11/12
(D) 12/13
(E) 13/14
P(At least One Red marble and One Green marble) = P(Total) -[\(\frac{P(Only Red Marble) + P (Only Green Marble)}{P(Any Marble)}\)] --- (1)
P(Total) = 1 --- (2)
P(Any Marble) = \(C^8_4\) = 70 --- (3)
P(Only Red Marble) =\(C^5_4\) = 5 --- (4)
P(Only
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