Bunuel wrote:
If \(\sqrt[3]{x - b} = c^6\), then \(x =\) ?
A. c^2 + b
B. c^6 + b
C. c^9 + b
D. c^12 + b
E. c^18 + b
x-b = c^18
x= c^18+b
IMO E
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If \(\sqrt[3]{x - b} = c^6\), then \(x =\) ?
A. c^2 + b
B. c^6 + b
C. c^9 + b
D. c^12 + b
E. c^18 + b
x-b = c^18
x= c^18+b
IMO E
Posted from my mobile device
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