Tmoni26 wrote:
Damm, it really is a knockout question
No of factors in a perfect square is odd, therefore B would be even
Test it
Say 36....no of factors is A = 9, then B = 9^3 - = even integer
Therefore odd x even must be even, so the answer is sufficiently no .........Sufficient
Stmt 2. A could be 2*3 = even or, 3*5 = odd
If A is even, then B must be even for (B+ 3^11) to be odd, and for the total sum of A+ (B+ 3^11) to be odd, therefore A*B is even
If A is odd, then B must be odd for (B + 3 ^11) to be
...
