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Problem Solving (PS) | Re: If k and m are numbers such that k + m = 20 and k^2 + m^2 = 289, then

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mvictor wrote:

Bunuel wrote:
lgarces19 wrote:
If k and m are numbers such that k + m = 20 and k^2 + m^2 = 289, then the value of the product km is

(A) between 20 and 60
(B) between 60 and 100
(C) between 100 and 150
(D) between 150 and 200
(E) greater than 200


Square k + m = 20;

(k + m)^2 = 20^2;

k^2 + 2km + m^2 = 400.

Since given that k^2 + m^2 = 289, then 289 + 2km = 400.

km = 111/2 = 55.5.

Answer: A.

P.S. Is this question really from GMAT Prep?



clearly, I need to brush up my quant skills...I took into consideration that k and m are

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