It is just extended version of your explanation for statement 1.
Statement 1 is about 3 consecutive even integers which are sides of right angle triangle.
So 6, 8 and 10 is right triplet satisfying this condition.
What is the length of the hypotenuse of ΔABC?
STATEMENT (1) The lengths of the three sides of ΔABC are consecutive even integers.
let the two legs be --n and n+1 hypotenuse n+2
then\((n+2)^2\) =\(n^2\)+\((n+1)^2\)
(n+1)(n-3)=0
n =3 (n cant be -ve value)
hypotenuse = 5
SUFFICIENT
STATEMENT
...
Statement 1 is about 3 consecutive even integers which are sides of right angle triangle.
So 6, 8 and 10 is right triplet satisfying this condition.
shridhar786 wrote:
What is the length of the hypotenuse of ΔABC?
STATEMENT (1) The lengths of the three sides of ΔABC are consecutive even integers.
let the two legs be --n and n+1 hypotenuse n+2
then\((n+2)^2\) =\(n^2\)+\((n+1)^2\)
(n+1)(n-3)=0
n =3 (n cant be -ve value)
hypotenuse = 5
SUFFICIENT
STATEMENT
...
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