Bunuel wrote:
What is the remainder when \(2^{1344452457}\) is divided by 11?
A. 2
B. 4
C. 5
D. 7
E. 9
The easiest and quickest way to solve this question is by pattern by using the formula=> dividend = divisor x quotient + remainder
2^1= 11(0) + 2 =>r=2
2^2= 11(0) + 4 =>r=4
2^3= 11(0) + 8 =>r=8
2^4= 11(1) + 5 =>r=5
2^5= 11(2) + 10 =>r=10
2^6= 11(5) + 9 =>r=9
2^7= 11(11) + 7 =>r=7
2^8= 11(23) + 3=>r=3
2^9= 11(46)+6=>r=6
2^10= 11(93)+1=>r=1
2^11= 11(186)+2=>r=2
2^12= 11(372)+4=>r=4
....
....
....
Notice
...










