Problem Solving (PS) | Re: Time, Speed and Distance

First, we shall find when & where willB catch up toA :
AsA moved3 hours earlier, the distance between them was60*3 = 180 km
The time needed byB to catch up toA = \(\frac{180}{90-60} = 6\) hours
In6 hours, TrainB will have traveled90*6 = 540 km

So the left distance that TrainC should have traveled to meedA & B = 1260 - 540 = 720 km

As trainB & C started traveling at the same time,C must have traveled for6 hours same asB .
so the speed ofC = \( \frac{720}{6} \)
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