Bunuel wrote:
If a < b, is a > 0?
(1) a^2 < b^2
(2) a^2 < ab < b^2
Given: a <b
Asked: Is a > 0?
(1)\(a^2 < b^2\)
|a|<|b|
a can be +ve or -ve and b must be +ve
NOT SUFFICIENT
(2) a^2 < ab < b^2
ab > a^2 > 0
ab>0
a & b have samesign
\(a^2 < ab < b^2\) => |a|<|b|
a can be +ve or -ve and b must be +ve
But a & b have same sign
b = +ve => a = +ve
a>0
SUFFICIENT
IMO B
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