Problem Solving (PS) | Re: If x & y are integers, how many solution pairs (x,y) satisfy the equat

Given: x & y areintegers
Asked: How many ordered pairs (x,y) satisfy the equation(|x-2|-12)(|y+4|-36)=72?

\(72 = 2^3*3^2\)
72 has 4*3 = 12 factors
Factors of 72 = {1,2,3,4,6,8,9,12,18,24,36,72}

If x & y are positive integers, we will have 12 cases

72=1*72 72= (|x-2|-12)(|y+4|-36)
|x-2|-12=1 => |x-2|=12+1=13 =>x=2+-13 => x=15 or x=-11
|y+4|-36=72
...

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