ttaiwo wrote:
Hi Bunuel,
I also plugged in 2 for P...and got pretty lost from there once I found out that P=2 as well.
I followed your explanation and understand P@ = 2 since when you plug in 2...the result is 2.
However, I don't follow what happens from there...how exactly is P@@=P?
As for solution 2: how did you solve this algebraically? In other words, how did you end up knowing that P@@ required you to dividing P/P-1 P/P-1 -1
Thanks
Posted from my mobile device
...









