$ 0 0 Bunuel wrote:Find 0.12÷12A. 100B. 10C. 1D. 0.01E. 0.0010.12 ÷ 12 \(= \frac{0.12}{12}= \frac{1.2}{120}= \frac{12}{1200}= \frac{1}{100}=0.01\)Answer: DCheers,Brent