For line AB, you have to consider 135 degree angle to calculate the slope
Slope of line AB= tan(135°)=-1
Slope of CD= tan120°=\(-\sqrt{3}\)
Bunuel chetan2u
VeritasKarishma
Hi, please see the attached image
Which angle do we take while considering the slope?
in line AB and CD(both -ve slopes)
AB makes an angle of 45 and CD angle of 60 with x axis so slope of CD<AB as CD is more negative
but if i see external angles of same lines then AB<CD in slope as 135<120 so 135 will be more negative
So
...
Slope of line AB= tan(135°)=-1
Slope of CD= tan120°=\(-\sqrt{3}\)
vanam52923 wrote:
Bunuel chetan2u
VeritasKarishma
Hi, please see the attached image
Which angle do we take while considering the slope?
in line AB and CD(both -ve slopes)
AB makes an angle of 45 and CD angle of 60 with x axis so slope of CD<AB as CD is more negative
but if i see external angles of same lines then AB<CD in slope as 135<120 so 135 will be more negative
So
...
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