In case it doesn't strike you to arrange the algebra, you can do the question the following way
St 1 : 4y^2 + 3x^2 = x^4 + y^4
Notice that 4y^2 is always going to be even.
Therefore, whether LHS is even or odd will depend upon the value of x.
If x = even,
then LHS is even. RHS will also have to be even. In RHS, since x is even, y will also be even. (if y is odd, then LHS will not be equal to RHS)
If x = odd,
then LHS is odd. RHS will also have to be odd. In RHS, since x is odd, y will have
...
St 1 : 4y^2 + 3x^2 = x^4 + y^4
Notice that 4y^2 is always going to be even.
Therefore, whether LHS is even or odd will depend upon the value of x.
If x = even,
then LHS is even. RHS will also have to be even. In RHS, since x is even, y will also be even. (if y is odd, then LHS will not be equal to RHS)
If x = odd,
then LHS is odd. RHS will also have to be odd. In RHS, since x is odd, y will have
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