radheykulkarni wrote:
dcbark01 wrote:
I used the Binomial Theory (which I admit I'm a little shaky on...)
1. We need to find a relationship between our dividend (2^86) and divisor (9)
2^86 = (2^2)*(2^84) = 4*(2^3)^28 = 4*(8)^28
We can expand this into binomial form as:
4*(9-1)^28
Every term will have a factor of 9 in it EXCEPT the last term (-1)^28 which is just equal to 1. Don't forget to distribute the 4 out, and voila, we have our remainder of 4*(1) = 4 therefore answer D.
1. We need to find a relationship between our dividend (2^86) and divisor (9)
2^86 = (2^2)*(2^84) = 4*(2^3)^28 = 4*(8)^28
We can expand this into binomial form as:
4*(9-1)^28
Every term will have a factor of 9 in it EXCEPT the last term (-1)^28 which is just equal to 1. Don't forget to distribute the 4 out, and voila, we have our remainder of 4*(1) = 4 therefore answer D.
In this what happens if the power
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