Problem Solving (PS) | Re: In how many ways can 6 chocolates be distributed among 3 children? A c

Let, three children get a, b and c chocolates respectively

i.e. a+b+c = 6

Now, the whole number solutions of an equation = (n+r-1)C(r-1) = (6+3-1)C(3-1) = 8C2 = 28

Answer: Option B

ALTERNATIVE
Let, three children get a, b and c chocolates respectively

i.e.
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