nick1816 wrote:
Intersection point of\(L_1\) and\(L_2\) is (0, 1) and that of\(L_1\) and\(L_3\) is (0, -1)
Center of the circle lies on perpendicular bisector of line\(L_1\)
Midpoint of Line\(L_1\) is (0, 0).
In center of the triangle=\(\frac{1}{2\sqrt{3}}\) *2=\(\frac{1}{\sqrt{3}}\)
Co-ordinates of center=(\(\frac{3}{\sqrt{3}}\) , 0)
Radius of circle=\(\frac{1}{\sqrt{3}}\)*2=\(\frac{2}{\sqrt{3}}\)
Kinshook wrote:
What is the equation of the circle C in which an equilateral triangle is inscribed which has lines L1 x =0, line L2\(\sqrt{3}y+x=\sqrt{3}\) and Line L3\(\sqrt{3}y-x+\sqrt{3}=0\) as its 3sides?
\(A. (x-\sqrt{3}/2)^2 + y^2 = \frac{4}{3}\)
\(B. (x-\sqrt{3}/3)^2+y^2=\frac{4}{3}\)
\(A. (x-\sqrt{3}/2)^2 + y^2 = \frac{4}{3}\)
\(B. (x-\sqrt{3}/3)^2+y^2=\frac{4}{3}\)
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