There is a positive number x => it has 8 positive factors. x =?
Well
i) IF product of any two factor is even then the number could be 2^3 * K where K is any odd prime number ( because then the # of _ve factors would be 8 { (3+1) * (1+1)}. Also this can be 2^7. So this option is NOT SUFFICIENT. Too many values of x
ii) This option states that this number x has 7 EVEN POSITIVE factors. We already know it has total 8 POSITIVE factors. And 1 is always a factor of this number. So, this number has
...
Well
i) IF product of any two factor is even then the number could be 2^3 * K where K is any odd prime number ( because then the # of _ve factors would be 8 { (3+1) * (1+1)}. Also this can be 2^7. So this option is NOT SUFFICIENT. Too many values of x
ii) This option states that this number x has 7 EVEN POSITIVE factors. We already know it has total 8 POSITIVE factors. And 1 is always a factor of this number. So, this number has
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