Quote:
If the 6 letters in the word NEEDED are randomly rearranged, what is the probability that the resulting string of letters will not be in alphabetical order?
A.17201720
B.11201120
C.160160
D.59605960
E.719720
The number of ways in which NEEDED can be rearranged is\(\frac{6!}{3! * 2!}\) = 60.
Only one way is possible to arrange in alphabetical manner. hence probability of not being in alphabetical order is 59/60
Option D.
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