OFFICIAL EXPLANATION
\(ABCD\) is a parallelogram.
Let\(AB\) and\(CD\) measure\(p\) units and\(AD\) and\(BC\) measure\(q\) units and height of the parallelogram be\(h\) units
Therefore, Area of the parallelogram =\(ph\)
\(2(p + q) = 12\)
\(p + q = 6\) ------------(I)
\(∠ADC = 120^{\circ}\)
This implies\(∠BAC = ∠BCD = 60^{\circ}\)
Since ΔAED is a 30-60-90 triangle, applying the angle-side property (1:√3:2)
\(h=\frac{q√3}{2}\) and\( AE=\frac{q}{2} \)
...
\(ABCD\) is a parallelogram.
Let\(AB\) and\(CD\) measure\(p\) units and\(AD\) and\(BC\) measure\(q\) units and height of the parallelogram be\(h\) units
Therefore, Area of the parallelogram =\(ph\)
\(2(p + q) = 12\)
\(p + q = 6\) ------------(I)
\(∠ADC = 120^{\circ}\)
This implies\(∠BAC = ∠BCD = 60^{\circ}\)
Since ΔAED is a 30-60-90 triangle, applying the angle-side property (1:√3:2)
\(h=\frac{q√3}{2}\) and\( AE=\frac{q}{2} \)
...








