Problem Solving (PS) | Re: In the above diagram, the circle inscribes the larger equilateral,

Using this information, we can create a 30-60-90 triangle (inblue)


We can now compare this blue 30-60-90 triangle with theBASE 30-60-90 triangle

By the property of similar triangles, we know that the ratios of corresponding sides will be equal.
That is:1/√3 =r/2
Cross multiply to get: (√3)(r) = 2
Solve: r = 2/√3
So, the RADIUS of the circle = 2/√3

HelloGMATPrepNow

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