First method (plug-in)
S=100 fall=20% so increase is 25% (20*100/80). Only Option E gives 25%
Second method
N=S*(1-J) D=S; Increase is S-S*(1-J)=S-S+SJ=SJ; % Increase = SJ/S*(1-J); S is eliminated to get J/(1-J) IMO E
S=100 fall=20% so increase is 25% (20*100/80). Only Option E gives 25%
Second method
N=S*(1-J) D=S; Increase is S-S*(1-J)=S-S+SJ=SJ; % Increase = SJ/S*(1-J); S is eliminated to get J/(1-J) IMO E









