frichmond wrote:
for the question 3^7^11:
Given the form 3^a, could you also say that a = 7^11 = (8-1)^11 and thus a = -1^11 = -1
therefore a is one less than a full cycle of 4 (ie 3 more than a multiple of 4) and thus 3^a will result in a units digit of 7
please let me know if this logic is sufficient
Yes, if you want to know the remainder when 7^11 is divided by 4, it's completely fine to replace the base '7' with any other number with a remainder of 3 when divided by 4 (though you certainly can't change
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