email2vm wrote:
Hi Bunuel,
I am not able to find the solution with this method.
x be the width of the surrounding
pi (8-x)^2/pi(8)^2 = 3/4
does not lead to the answer..I am not able to find whats wrong in this approach.
Please help.
Regards,
Ravi
There is nothing wrong with thisapproach.
\frac{\pi (8-x)^2}{\pi(8)^2} = \frac{3}{4} -->(8-x)^2=48 -->8-x=4\sqrt{3}=6.9 -->x=8-6.9=1.1 .
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