Formula to be used:
Pythagoras theorem:\(Hypotenuse^2\) =\(Base^2\) +\(Perpendicular^2\)
Total distance walked by Mary =\(PQ + QR = 8 + 6 = 14 miles\)
Total distance walked by Ted = PR
Applying Pythagoras theorem in the TrianglePQR:
\(PR^2\) =\(PQ^2\) +\(QR^2\)
\(PR^2\) =\(8^2\) +\(6^2\) \(= 64 + 36 = 100\)
PR = +10 OR -10
Since PR is a distance and cannot be negative, PR = 10 miles
The difference in the distance walked by Mary and Ted = 14 - 10 = 4 miles
Percent of the distance that Mary walked more than Ted walked =
...
Pythagoras theorem:\(Hypotenuse^2\) =\(Base^2\) +\(Perpendicular^2\)
Total distance walked by Mary =\(PQ + QR = 8 + 6 = 14 miles\)
Total distance walked by Ted = PR
Applying Pythagoras theorem in the TrianglePQR:
\(PR^2\) =\(PQ^2\) +\(QR^2\)
\(PR^2\) =\(8^2\) +\(6^2\) \(= 64 + 36 = 100\)
PR = +10 OR -10
Since PR is a distance and cannot be negative, PR = 10 miles
The difference in the distance walked by Mary and Ted = 14 - 10 = 4 miles
Percent of the distance that Mary walked more than Ted walked =
...








