This problem takes more time to read than to solve![Image]()
F(n) = (n^2)!
F(3) = 9! [Powers of 2 = 7] .............(1)
G(n) = 1^2 * 2^2 * 3^2 .......... n^2 = (n!)^2
G(3) = (3!)^2 = 36 [Powers of 2 = 2] ............ (2)
\frac{(1)}{(2)}[Powers of 2 = 7-2 = 5]
Answer = E
...
F(n) = (n^2)!
F(3) = 9! [Powers of 2 = 7] .............(1)
G(n) = 1^2 * 2^2 * 3^2 .......... n^2 = (n!)^2
G(3) = (3!)^2 = 36 [Powers of 2 = 2] ............ (2)
\frac{(1)}{(2)}[Powers of 2 = 7-2 = 5]
Answer = E
...
