Problem Solving (PS) | Re: There are 6 concentric squares and a circle is inscribed in the smalle

\(pi*d^2/4=77\)
\(d^2=98\)
\(d=7\sqrt{2}\)
Diameter of circle= Length of side of innermost circle=\(7\sqrt{2}\)
Area of innermost square=\((side)^2\) =98

Now the distance between the sides of 2 consecutive squares,x =\(\frac{2}{\sqrt{2}}\)\(x=\sqrt{2}\)

Side of outermost square= Side of inner most square+10x= 7\(\sqrt{2}\)\(10\sqrt{2}\)
Side of outermost square= 17\(\sqrt{2}\) Area of outermost square=\((side)^2\) =578

sum of areas of the outermost and innermost square= 578+98=676




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