Mo2men
Yes, I did. Since nothing to the contrary is mentioned that is an automatic assumption.
There is actually a quicker way of solving this:
3 extra days means 3*3=9 man-days have been lost due to abstentions. Let's say Carol absented for 'y' days. Then, Adam and Bart absented for (y+2) and (y+4) days respectively. Consequently, [y+(y+2)+(y+4)]=(3y+6) man-days were lost.
So, 3y+6=9---> y=1
Yes, I did. Since nothing to the contrary is mentioned that is an automatic assumption.
There is actually a quicker way of solving this:
3 extra days means 3*3=9 man-days have been lost due to abstentions. Let's say Carol absented for 'y' days. Then, Adam and Bart absented for (y+2) and (y+4) days respectively. Consequently, [y+(y+2)+(y+4)]=(3y+6) man-days were lost.
So, 3y+6=9---> y=1
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