$ 0 0 raghavrf wrote:The smallest integer n for which \(4^n\) > \(17^{19}\) holds, is closest to(a) 31(b) 33(c) 35(d) 37(e) 39Source: testbook.com\(4^n\) > [m]17^{19}[/m4^n>(16)^19+1^194^n>4^38+1^19n>=38n=39 IMOE