tank r cost = 2250 $ is same as the vol of tank - 2250 ; pi * r^2 *h = 2250
now for tank S we need its r and h values
#1
Dr= 2Ds
not sufficient as h is missing radius of s = radius of R /4
#2
h is same , r is missing
from 1 & 2
pi* r2*h /4 = 2250/4 ; 562.5$
IMO C
It costs $2,250 to fill right circular cylindrical Tank R with a certain industrial chemical. If the cost to fill any tank with this chemical is directly proportional to the volume of the chemical needed to fill the tank, how much
...
now for tank S we need its r and h values
#1
Dr= 2Ds
not sufficient as h is missing radius of s = radius of R /4
#2
h is same , r is missing
from 1 & 2
pi* r2*h /4 = 2250/4 ; 562.5$
IMO C
Bunuel wrote:
It costs $2,250 to fill right circular cylindrical Tank R with a certain industrial chemical. If the cost to fill any tank with this chemical is directly proportional to the volume of the chemical needed to fill the tank, how much
...