If x^2=y^2, is it true that X>0?
|x|=|y| ---> x=y or x=-y
1. x=2y+1, x is also equal to y. --> 2y+1=y or y=-1. If y=-1, x=2(-1)+1=-2+1=-1
x=2y+1, x is also equal to -y. --> 2y+1=-y or y=-(1/3). If y=-(1/3), x=-(2/3)+1=(-2+3)/3=1/3
we see that x is positive in second case and not in the first. NOT SUFFICIENT
2. y<=-1. This one is easy to notice that x can be anything as long as its magnitude is same as y's.
1+2: y can only be -1 from combining these two statement. This is
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|x|=|y| ---> x=y or x=-y
1. x=2y+1, x is also equal to y. --> 2y+1=y or y=-1. If y=-1, x=2(-1)+1=-2+1=-1
x=2y+1, x is also equal to -y. --> 2y+1=-y or y=-(1/3). If y=-(1/3), x=-(2/3)+1=(-2+3)/3=1/3
we see that x is positive in second case and not in the first. NOT SUFFICIENT
2. y<=-1. This one is easy to notice that x can be anything as long as its magnitude is same as y's.
1+2: y can only be -1 from combining these two statement. This is
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