Bunuel wrote:
If \((x+5) (\frac{1}{x}+\frac{1}{5})=4\), then x=
A. \(\frac{1}{5}\)
B. \(\frac{1}{2}\)
C. 1
D. 5
E. 10
solve for expression\((x+5) (\frac{1}{x}+\frac{1}{5})=4\)
we get
(x+5)^2=20x
solve
x^2-10x+25=20x
or say (x-5)(x-5)
x=+5
IMO D
...
If \((x+5) (\frac{1}{x}+\frac{1}{5})=4\), then x=
A. \(\frac{1}{5}\)
B. \(\frac{1}{2}\)
C. 1
D. 5
E. 10
solve for expression\((x+5) (\frac{1}{x}+\frac{1}{5})=4\)
we get
(x+5)^2=20x
solve
x^2-10x+25=20x
or say (x-5)(x-5)
x=+5
IMO D
...
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