GMAT Quantitative Section | Regular hexagon ABCDEF has a perimeter of 36. O is the

My approach was as follows :

1. Area of hexagon : 6 * \sqrt{3} / 4 * 3 * 3

2. Now calculate the area of 6 sectors of circles of angle 120 degree using sector formula : 120/360 * 3.14 * 3 * 3

3. Area of step 2 + Area of another circle : 3.14 * 3 * 3

4. Final Solution : Area of hexagon(step 1) - (Area of sectors+Area of 7th circle)(Step 3)

---