pratikshr wrote:
If A \neq 0, is \frac{1}{A} > \frac{A}{B^4+3} ?
(1) A = B^2
(2) A^2 = B^4
It's a Yes/No question. From question itself we can deduce that(B^4+3) will always be positive.
Rephrasing question ->\frac{B^4+3}{A} > \frac{A}{1} ?
Note that ,we can not multiply A in this inequality since A might be negative too.
Stmt 1 -
A = B^2 => A is square of some number (B in this case) so A will always be positive. So multiply with A both side ->
squaring statement 1 at both sides
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