Bunuel wrote:
If x, y and z are positive numbers, is \(\frac{x}{y} > \frac{x + z}{y + z}\) ?
(1) x > z
(2) x > y
From given eqn we can deduce thefollowing:
xy+xz>xy+yz
z(x-y)>0--(A )
so using 1: x>z , we are not given any relation about y so in -sufficient
From 1: X>Y
for any value of X >Y value the equation ( A) would stand true so B is sufficient..
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