Data Sufficiency (DS) | If x^y = 1 then what is the value of x?

Most important element to answer this question is to know that any number raise to "0" is 1. (e.g. 1^0 =1 or -1^0=1)

Now let's work this out.

x^y=1,x=?

St 1: x<0 (x is -ve)

Case 1: -1^2 = 1
Case 2: -2^0 = 1

Therefore X could be -1,-2,-3 or any -ve number if the power is 0. InsufficientAD /BCE

St 2: Y is even
(Note: 0 is an even number)

Case 1: x=1, y=2
1^2=1
Case 2: x=2, y=0
2^0=1

Hence B is insufficient.AD/B CE

St1 + St2
x^y=1 (x<0, y is even)

Case 1: x=-1 and y=2
=>
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