GMAT Problem Solving (PS) | Re: Rectangle ABCD with a perimeter of 60 is inscribed in a circ

Refer diagram below:

Perimeter = 60

If one side = x, then

other side would be = 30 - x

Diameter of circle = Diagonal of rectangle

= 2* 7.5\sqrt{2}

= 15\sqrt{2}

Setting up theequation

(15\sqrt{2})^2 = x^2 + (30-x)^2

x^2 - 30x + 225 = 0

(x - 15)^2 = 0

x = 15

Area = 15 * 15 = 225 (This rectangle is a square)

Answer = B

Bunuel, Kindly update the OA

One more thing,

I understand that every square is a rectangle & every rectangle NEED NOT have to be a square.
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