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GMAT Data Sufficiency (DS) | Re: Triangle T has vertices of (-2,6), (6,2) and (0,k) where k

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Area=1/2 * [x1(y3-y2) + x2(y1-y3) +x3(y2-y1] as posted by alphabeta1234

Area = 1/2|(x1-x3)(y2-y1)- (x1-x2) (y3-y1)| as posted by raingary

Area = |1/2 ( x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2))|as posted by VeritasPrepKarishma

Seeing the same formula represented in 3 different ways has confused me a little
Can someone explain the formula in the most basic form, giving the necessary fundamentals.

And show how we are arriving to the three different forms as shown above.
Thank you

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