Problem Solving (PS) | Re: A set of 51 different integers has a median of 30 and a range of 60.

median is 30 which is the 26th number in the series.
In order to minimize the lowest number, we need to minimize the maximum number.
Because,
(X)(smallest highest number) - (Y)(least negative number) = 60 (to minimize Y)

the smallest highest number possible for this series is 55. Because \(30+25 = 55\). 25 different integers ahead of the median.

Therefore,

\(55 - x = 60\)
\(x=-5\)

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